A monochromatic source of light is placed at a large distance d from a metal surface Photoelectrons are ejected at rate n,kinetic energy being E. If the source is brought nearer to distance d/2, the rate and kinetic energy per photoelectron become nearly
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Maximum kinetic energy will the same as E , because kinetic energy doesn't depend upon intensity of photoelectrons , kinetic energy just depends upon frequency of incident photons.
As you know, by the formula
But in case of intensity , it depends upon distance between source and metal surface [ ∵ I = P/4πd², for point source , here P is the power and d is the distance between source and metal surface ]
so, if d will be half then intensity will be 4 times
Hence, final intensity = 4I
Here mentioned rate of photoelectrons per unit area , this is what , of course intensity hence, rate of photoelectrons per unit area = 4n
Hence, answer is 4n and E
As you know, by the formula
But in case of intensity , it depends upon distance between source and metal surface [ ∵ I = P/4πd², for point source , here P is the power and d is the distance between source and metal surface ]
so, if d will be half then intensity will be 4 times
Hence, final intensity = 4I
Here mentioned rate of photoelectrons per unit area , this is what , of course intensity hence, rate of photoelectrons per unit area = 4n
Hence, answer is 4n and E
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Answer:
hello please like my answer
Explanation:
E and 4n is your answer
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