A monochromatic source of wavelength 600nm was used in YSD exp.to produce interference pattern.I is the intensity of light at a point on the screen where the path diff is 150nm.The intensity of light at a point where the path diff is 200nm is given by?
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Given that,
Wavelength = 600 nm
Intensity is I, where the path difference is 150 nm
We know that,
The formula of intensity is
We need to calculate the value of θ
Using formula of path difference
Where, = path difference
= wave length
Put the value into the formula
We need to calculate the intensity
Using equation (I)
Here,
Put the value of θ
We need to calculate the value of of θ
Using formula of path difference
Put the value into the formula
We need to calculate the intensity
Using equation (I)
Put the value of θ
Put the value of
Hence, The intensity of light at a point will be I.
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