A monoenergetic radiation beam is having a wavelength 0.5 micrometer. What is a energy of single photon in eV.
Answers
we know that,
Energy=hc/wavelength
= 6.62*10-34×3*10+8/5*10-7
= 3.97*10-19 J
1Joule=6.62*10-18ev then,
3.97*10-19J =6.62*10-18×3.97*10-19
= 2.628ev
hope this will help you
The energy of the single photon is 2.484 eV.
Method I:
The wavelength of the mono energetic beam = 0.5 micrometer (μm)
= 5000 A⁰ (Angstrom)
∵ 1 μm = 10⁻⁶ m
and, 1 A⁰ = 10⁻¹⁰ m
∴ 1 μm = 10⁴ A⁰
Now, we know, the most simple formula of calculating
The energy of a single photon = eV
By putting the values, we get,
The energy of a single photon = 12420/5000 eV
= 2.484 eV
∴ The energy of a single photon is 2.484 eV
Method II:
We know, the energy of a single photon, E = hc/λ
where h = Planck's constant
c = speed of light
λ = wavelength
Now, h = 6.62 × 10⁻³⁴ Js
c = 3 × 10⁸ m/s
λ = 0.5 micrometer
= 0.5 × 10⁻⁶ [∵ 1 μm = 10⁻⁶ m]
By putting these values in the above equation, we will get the value of E in Joule.
And 1 Joule = 6.242 × 10¹⁸ eV
As in the question we are asked to calculate it in eV, we have to multiply the value with 6.242 × 10¹⁸
We will get, the energy of single photon = 4.484 eV.