A mosquito travels in a 3 - dimensional space with the velocity field overline F =(3x^ 2 +6y) hat i -14yz hat j +20xz^ 2 hat k in such a way that its position vector is Find the work done by the mosquito to travel from the point overline r (t)=t hat i +t^ 2 hat j +t^ 3 hat k (0, 0, 0) to (1. 1. 1) .
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Answer:
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.An odd number is 1 more (or 1 less) than an even number. And so we represent an odd number as 2n + 1.
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.An odd number is 1 more (or 1 less) than an even number. And so we represent an odd number as 2n + 1.Let 2n + 1, then, be the first odd number. Then the next one will be 2 more -- it will be 2n + 3. The problem states that their sum is 52:
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.An odd number is 1 more (or 1 less) than an even number. And so we represent an odd number as 2n + 1.Let 2n + 1, then, be the first odd number. Then the next one will be 2 more -- it will be 2n + 3. The problem states that their sum is 52:2n + 1 + 2n + 3 = 52.
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.An odd number is 1 more (or 1 less) than an even number. And so we represent an odd number as 2n + 1.Let 2n + 1, then, be the first odd number. Then the next one will be 2 more -- it will be 2n + 3. The problem states that their sum is 52:2n + 1 + 2n + 3 = 52.We will now solve that equation for n, and then replace the solution in 2n + 1 to find the first odd number. We have:
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.An odd number is 1 more (or 1 less) than an even number. And so we represent an odd number as 2n + 1.Let 2n + 1, then, be the first odd number. Then the next one will be 2 more -- it will be 2n + 3. The problem states that their sum is 52:2n + 1 + 2n + 3 = 52.We will now solve that equation for n, and then replace the solution in 2n + 1 to find the first odd number. We have:4n + 4 = 52
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.An odd number is 1 more (or 1 less) than an even number. And so we represent an odd number as 2n + 1.Let 2n + 1, then, be the first odd number. Then the next one will be 2 more -- it will be 2n + 3. The problem states that their sum is 52:2n + 1 + 2n + 3 = 52.We will now solve that equation for n, and then replace the solution in 2n + 1 to find the first odd number. We have:4n + 4 = 524n = 48
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.An odd number is 1 more (or 1 less) than an even number. And so we represent an odd number as 2n + 1.Let 2n + 1, then, be the first odd number. Then the next one will be 2 more -- it will be 2n + 3. The problem states that their sum is 52:2n + 1 + 2n + 3 = 52.We will now solve that equation for n, and then replace the solution in 2n + 1 to find the first odd number. We have:4n + 4 = 524n = 48n = 12.
First, an even number is a multiple of 2: 2, 4, 6, 8, and so on. It is conventional in algebra to represent an even number as 2n, where, by calling the variable 'n,' it is understood that n will take whole number values: n = 0, 1, 2, 3, 4, and so on.An odd number is 1 more (or 1 less) than an even number. And so we represent an odd number as 2n + 1.Let 2n + 1, then, be the first odd number. Then the next one will be 2 more -- it will be 2n + 3. The problem states that their sum is 52:2n + 1 + 2n + 3 = 52.We will now solve that equation for n, and then replace the solution in 2n + 1 to find the first odd number. We have:4n + 4 = 524n = 48n = 12.Therefore the first odd number is 2 · 12 + 1 = 25. And so the next one is 27. Their sum is 52.