A motar bike initially moving at 18km/h acceleration at the rate of 5m/s^2 for 5s calculat. the final velocity ?
Answers
Answered by
0
Answer:30ms^-1
Explanation:first, we have to make the unit same..i m making km/h to ms^-2.
18km/h=5ms^-1
Then..we have to go ahead from formulae v=u+at
V=u+at
V=5+5×5
V=30ms^-1
Answered by
0
Answer:
30m/s
Explanation:
here u=18km/h=5m/s
a=5m/s^2
t=5s
v=u+at
v=5+5×5=30m/s
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