Physics, asked by krishnasrivastava190, 9 months ago

A motar boat starting from rest on a lake to accelerate in a straight line at a constent rate of 3.0m/sec².How far does the boat travel during this time?​

Answers

Answered by Anonymous
9

Answer:

96 metres

Explanation:

Given :

  • Initial velocity = u = 0 m/s

  • Acceleration of the motor boat = a = 3 m/s²

  • Time taken = 8 seconds (time is not given and i have assumed it as 8 seconds as it is a ncert question)

To find :

  • Distance travelled by the motor boat

Using second equation of motion :

S=ut+½×at²

S=0×8+½×3×8×8

S=0+96

S=96

The distance travelled by the motor boat is equal to 96 metres assuming the time equal to 8 seconds

Answered by MsPRENCY
13

Ques Error :

Time : 8 sec.

______________

Answer :

Motor boat will cover  96 m  during the given time.

\rule{100}2

It is given that,

  • u = 0 m/s
  • a = 3 m/s²
  • t = 8 sec
  • s = ?

We know that,

S = ut + 1/2 at²

Substitute the given values. We get,

S = 0 × 8 + 1/2 ( 3 ) ( 8 )²

⇒ s = 0 + 1/2 ( 3 ) ( 64 )

⇒ s = 96 m  

Therefore,

The motor boat will cover 96 m distance.

\rule{200}2

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