Question

A motarboat starting from rest on a lake accelerates in a straight line at a constant rate of 3.0 ms-2 for 8.0 s. How far does the boat travel during this time
??

Answer 1

Answer:96 meters

Explanation: the formula for the distance of horizontal motion of an object is d =½at² from the general formula of d=vi(t) +½at², since the inital velocity is 0 we can remove it from the equation.

Given:

a=3m/s²

t=8.0s

Solution:

d = ½at²

d = ½(3m/s²)(8s)²

d = ½(3m/s²)(64s²); cancel s² and divide 64 by 2 which is 32

d = (3m)(32)

d = 96m

Answer 2

Answer:

Known Terms:-

u = Initial speed

v = Final speed

a = Acceleration

t = Time

s = Distance

Given:-

Initial speed of the motorboat, u = 0 km

Acceleration attain by the motorboat, a = 3 m/s

Time taken by the motorboat, t = 8 sec

To Find:-

Distance Travelled

Formula to be used:-

Motion 2nd equation that is $s=ut+\frac{1}{2}at^2$

Solution:-

Putting all values, we get

⇒ $s=ut+\frac{1}{2}at^2$

⇒ $s=0+\frac{1}{2}(3)(8)^2$

⇒ $s=96 \: m.$

Hence, the distance travelled by motorboat is 96 m.