Math, asked by globalsunshine3, 10 months ago

A motel has ten rooms, all located on the same side of a single corridor and numbered 1 to 10 in numerical order. The motel always randomly allocates rooms to its guests. There are no other guests besides those mentioned.

a) Friends Molly and Polly have been allocated two separate rooms at the motel. What is the likely number of rooms between their rooms?
b) Molly believes there is a greater than 1/3 chance that at most one room will separate them, but Polly disagrees. Who is right? Explain why,
c) On another occasion, Molly, Polly and a third friend, Ollie, were allocated three separate rooms. Molly believes there is a better than 1/3 chance that they are all within a block of five consecutive rooms. Ollie believes that there is exactly 1/3 chance and Polly believes there is less than 1/3 chance. Who is right? Explain why.
d) Ollie arrived after rooms were allocated to Molly and Polly. There was then a 50% chance he would be in a room adjacent to Molly or Polly or both. In how many ways could a pair of rooms have been allocated to Molly and Polly?

Answers

Answered by ayarya7318
0

Answer:

Your Answer is 48.

• Kindly refer to the attachment dear !

- Regards

@dmohit432

Answered by amitnrw
2

Given : A motel has ten rooms ,  all located on the same side of a single corridor and numbered 1 to 10 in numerical order.  Friends Molly and Polly have been allocated two separate rooms at the motel.

To find : the likely number of rooms between their rooms

Solution:

Moly probability                Rooms in between  probability

Room           0         1        2      3        4       5      6       7      8          

1    (1/10)       1/9    1/9     1/9    1/9     1/9     1/9    1/9    1/9    1/9    

2   (1/10)       2/9    1/9     1/9    1/9     1/9     1/9    1/9    1/9    0    

3  (1/10)        2/9    2/9     1/9    1/9     1/9     1/9    1/9    0     0    

4  (1/10)         2/9    2/9    2/9    1/9     1/9     1/9    0     0      0      

5  (1/10)         2/9    2/9    2/9    2/9     1/9     0      0     0       0      

6  (1/10)         2/9    2/9    2/9    2/9     1/9     0      0     0       0

7  (1/10)         2/9    2/9    2/9    1/9     1/9     1/9     0      0      0

8  (1/10)         2/9    2/9     1/9    1/9     1/9     1/9    1/9    0     0      

9  (1/10)         2/9    1/9     1/9    1/9     1/9     1/9    1/9    1/9    0    

10  (1/10)        1/9    1/9     1/9    1/9     1/9     1/9    1/9    1/9    1/9    

Probability  18/90  16/90 14/90 12/90 10/90 8/90 6/90 4/90 2/90

 Likely number of rooms between their rooms

= 0 * (18/90) + 1 * (16/90) + 2(14/90) + 3(12/90) + 4(10/90) + 5(8/90) + 6(6/90)  + 7(4/90) + 8(2/90)

=  (1/90)(0 + 16 + 28 + 36 + 40 + 40 + 36 + 28 + 16)

= 240/90

=24/9

= 8/3

= 2.33 rooms

likely number of rooms between their rooms = 2.33

At most 1 room = 0 room or 1 room

= (18 + 16)/90

= 34/90

34/ 90 > 30/90

=> 34/90 > 1/3

=> Moly belief is right that    there is a greater than 1/3 chance that at most one room will separate them          

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