A moter bike starting from rest on a lake accelerates in a straight line at a constant rate of 3m/s2 for 5 second .How for does the boat travel during this time.
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S = ut + 0.5at^2
= 0 + (0.5 × 3 × 5^2)
= 37.5 m
Displacement covered during this time is 37.5 m
= 0 + (0.5 × 3 × 5^2)
= 37.5 m
Displacement covered during this time is 37.5 m
Answered by
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u=0
a=3m/s^2
t= 5sec
s=?
s= ut+1/2at^2
s= 1/2 x 3 x 25
s= 75/2
s= 37.5 m
a=3m/s^2
t= 5sec
s=?
s= ut+1/2at^2
s= 1/2 x 3 x 25
s= 75/2
s= 37.5 m
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