Question

a mother after 4 year will be twice the age of her daughter.the sum of their ages is 46 what is the present age of the daughter?​

Answer 1

Answer:-

Mother age = 32 years.

Daughter age = 14 years.

Solution:-

Let the age of mother be x years and daughter be y years.

A/Q.

The sum of their age is 46 years.

$x + y = 46$ -----eq. 1

Now, After 4 years mother age be twice the daughter age :-

Mother age after 4 years = ( x + 4)

Daughter age after 4 years = (y + 4)

then,

$(x +4) = 2(y+4) \\ x + 4 = 2y + 8 \\x - 2y = 8 - 4 \\ x - 2y = 4----eq.2$

Now , subtract both equation 1 and 2.

$x + y = 46 \\ x - 2y = 4$

$x - x + y -(-2y ) = 46-4 \\y + 2y = 42$

$3y = 42 \\ y = 14 years$

Put the value of y in equation 1.

$x + 14 = 46 \\ x = 46 - 14 \\ x = 32 years$

hence, Mother present age is = 32 years.

, Mother present age is = 32 years. Daughter present age is = 14 years.

Answer 2

Answer:

Mother age is 46

daughter age is 14