Math, asked by sandy23, 1 year ago

a mother and her 2 daughters got a room constructed for Rs. 62,000 the elder daughter contributed 3/8 of her mother's share. the younger daughter contributes 1/2 of her mother's share how much do the three contribute individually

Answers

Answered by Anonymous
2
Let the mother's share be x
elder daughter=3/8*x
younger daughter=1/2*x
Total money=62000
Sum of both daughters=62000
3x/8+x/2=62000
3x+4x/8=62000
7x/8=62000
7x=496000
x=496000/7
x=70857.14
Elder=3*70857.14/8
        =26571.42
Younger=70857.14/2
              =35428.58
Therfore Elder daughter's share =
26571.42
               
Younger daughter's share=35428.58
                Total sum =62000
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