Math, asked by manisenthilkum, 1 year ago

a mother and her two daughter got a room constructed for rs.62000. the elder daughter contributes 3/8 of her mother contribution while the younger daughter contributes 1/2 of her mother share.how much do the three contribute individually?


manisenthilkum: plzzzzzz

Answers

Answered by PADMINI
44
let mother contribute = x

elder daughter contribute = 3/8*x = 3x/8

younger daughter contribute = x/2

given - total contribution = 62000

x+3x/8+x/2=62000

8x+3x+4x/8=62000

15x/8=62000

15x=496000

x=496000/15

x=33067 .

hence , mother contribute = 33067

elder daughter contribute= 33067*3/8=12400

younger daughter contribute= 33067/2=16533

hope, it helps you ..

Answered by Anonymous
10
letter X be the amount contributed by mother.
amount contributed by elder daughter= 3x/8
amount contributed by younger daughter=X/2

total contribution= 62000
X + 3x/8 + X/2 = 62000
8x + 3x + 4x = 8 × 62000
15x = 496000
X= 496000/15
X= 33066.66


mother's contribution= 33067 ( approx)
elder daughter's contribution= 33066.66x3/8=12400

younger daughter contribution=33066.66/2= 16533







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