a mother and her two daughters got a room constructed for rupees 60000 the elder daughter contributes 3/8 of her mother's contribution while younger daughter contributes 1/2 of a mother's share how much do the three contributes individually
Answers
Answered by
5
Step-by-step explanation:
The elder daughter shared ₹22500
(60000÷3/8)
The younger daughter contributed ₹30000
the mother shared ₹7500
hope this would be correct
Answered by
10
Answer:
Ther-fore the total contribution=₹60000
Step-by-step explanation:
Since,we know the cost totally contributed ,we can find the others
ther-fore;
Daughter 1
the mother's share = x
according to the question,
elder daughter's contribution= 3/8 x
younger daughter's contribution = 1/2 x
now,
x +3x/8 + x/2 = 62000
(8x +3x+4x)/8 = 62000
15x = 496000
x = 496000/15
x = mother's share= 33067
3/8 x = elder daughter's share = 33067 × 3/8 = 12400
1/2 x = younger daughter's share = 33067/2 = 16533
that's all
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