Math, asked by sarah4740, 10 months ago

a mother and her two daughters got a room constructed for rupees 60000 the elder daughter contributes 3/8 of her mother's contribution while younger daughter contributes 1/2 of a mother's share how much do the three contributes individually ​

Answers

Answered by somendgp8
5

Step-by-step explanation:

The elder daughter shared ₹22500

(60000÷3/8)

The younger daughter contributed ₹30000

the mother shared ₹7500

hope this would be correct

Answered by EntroScientist
10

Answer:

Ther-fore the total contribution=₹60000

Step-by-step explanation:

Since,we know the cost totally contributed ,we can find the others

ther-fore;

Daughter 1

the mother's share = x

according to the question,

elder daughter's contribution= 3/8 x

younger daughter's contribution = 1/2 x

now,

x +3x/8 + x/2 = 62000

(8x +3x+4x)/8 = 62000

15x = 496000

x = 496000/15

x  = mother's share= 33067

3/8 x = elder daughter's share = 33067 × 3/8 = 12400

1/2 x = younger daughter's share = 33067/2 = 16533

that's all

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