Question

a mother and her two daughters got a room constructed for rupees 16000 the elder daughter contributes 3 by 8 of a mother's contribution while younger daughter contributes half for mother's share how much will the three contribute individually.

Answer 1

Answer:

Step-by-step explanation

Money contributed by mother be x

Money contributed by elder daughter is 3x/8

Money contributed by younger daughter is x/2

X + 3 X / 8 + X/2 =16000

15x/8=16000

15x=16000*8

x=16000*8/15

x=8533.3333...

So money contributed by mother is 85 33.33...

Money contributed by elder daughter

x/2=4266.666....

Money contributed by younger daughter=3x/8=3200

Answer 2

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Total money contributed by all three of them =Rs. 60000

Let the contribution of the mother be Rs. x.

Therefore,

The contribution by the elder son = $\frac{8}{3x}$

The contribution by the younger son =$\frac{2}{x}$

According to the question,x+ 8 by 3x + 2 upon x =60000

15x=480000

x=32000

Therefore, The contribution of the mother =Rs. x=Rs. 32000

The contribution by the elder son = 8 by 3x =Rs. 12000

The contribution by the younger son = 2 upon x =Rs. 16000