A mother and her two daughters got a room constructed for Rs 60,000. The elder daughter contributes 3/8 of her mother's contribution while the younger daughter contributes 1/2 of her mothers share. How much do the three contribute individually?
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Answer:
Step-by-step explanation:
MOTHERS SHARE = X
ELDER DAUGHTER SHARE = 3/8 OF X = 3X/8
YOUNGER DAUGHTER SHARE= 1/2 OF X = X/2
THEIR TOTAL SUM NEED TO BE= Rs. 60,000
3X/8 + X/2 + X = RS. 60,000
LCM = 8
3X/8 * 1/1 = 3X/8 ; X/2 * 4/4 = 4X/8 ; X * 8/8 = 8X/8
3X/8 + 4X/8 + 8X/8 = Rs. 60,000
15X/8 = Rs. 60,000
15X = 60,000 * 8
X = 60,000* 8 / 15
X= 4,000 * 8
X= 32,000
THEN, MOTHERS SHARE IS Rs. 32,000
ELDER DAUGHTER SHARE IS 3/8 * 32,000 = 3 * 4,000 = Rs. 12,000
YOUNGER DAUGHTER SHARE IS 1/2 * 32,000 = 1 * 16,000 = Rs. 16,000
AT LAST, WE CAN SAY
MOTHER , ELDER DAUGHTER , YOUNGER DAUGHTER ARE Rs. 32,000 , Rs. 12,000 , Rs. 16,000 RESPECTIVELY.
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