A mother and her two daughters got a room constructed for rs 62000.the elder daughter contributed 3/8 of her mothers contribution while the youngers contributes 1/2of her mothers share.how much do the three contribute individually?
Answers
Answered by
2
let,
the mother's share = x
according to the question,
elder daughter's contribution= 3/8 x
younger daughter's contribution = 1/2 x
now,
x +3x/8 + x/2 = 62000
(8x +3x+4x)/8 = 62000
15x = 496000
x = 496000/15
x = mother's share= 33067
3/8 x = elder daughter's share = 33067 × 3/8 = 12400
1/2 x = younger daughter's share = 33067/2 = 16533
the mother's share = x
according to the question,
elder daughter's contribution= 3/8 x
younger daughter's contribution = 1/2 x
now,
x +3x/8 + x/2 = 62000
(8x +3x+4x)/8 = 62000
15x = 496000
x = 496000/15
x = mother's share= 33067
3/8 x = elder daughter's share = 33067 × 3/8 = 12400
1/2 x = younger daughter's share = 33067/2 = 16533
Anonymous:
brainliest please.........
the answer is wrong i have the answers but dont know how to do it
i've solved it my self
and got the answer
check the values in the question u have
Answered by
4
Given :
A mother and her two daughters got a room constructed for Rs 62,000. The elder daughter contributes 3/8 of her mother's contribution while her younger daughter contributes 1/2 of her mother's share.
To Find :
How much do the three contribute individually ?
Solution :
Let mother contribute = x
Elder daughter contribute = 3/8*x = 3x/8
younger daughter contribute = x/2
Total contribution = 62000
According to the given question -
=> x+3x/8+x/2=62000
=> (8x+3x+4x)/8=62000
=> 15x/8=62000
=> 15x=496000
=> x=496000/15
=> x=33067 .
Hence , mother contribute = 33067
Elder daughter contribute= 33067*3/8=12400
Younger daughter contribute= 33067/2=16533
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