a mother and her two daughters got a room constructed for rs. 62,000. the elder daughter contributes 3/8 of her mother's contribution while the younger daughter contributes 1/2 of her mother's share.how much do the three contribute individually?
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4
let the contribution of mother= x
then 3x/8is contribution of elder daughter
x/2 is contribution of younger daughter
then,
3x/8+x/2+x=62000
15x/8=62000
15x=496000
x=33066.66
3x/8=12399.99
x/2=16533.33
then 3x/8is contribution of elder daughter
x/2 is contribution of younger daughter
then,
3x/8+x/2+x=62000
15x/8=62000
15x=496000
x=33066.66
3x/8=12399.99
x/2=16533.33
Answered by
3
Given :
A mother and her two daughters got a room constructed for Rs 62,000. The elder daughter contributes 3/8 of her mother's contribution while her younger daughter contributes 1/2 of her mother's share.
To Find :
How much do the three contribute individually?
Solution :
Let mother contribute = x
Elder daughter contribute = 3/8*x = 3x/8
younger daughter contribute = x/2
Total contribution = 62000
According to the given question -
=> x+(3x/8)+(x/2)=62000
=> (8x+3x+4x)/8=62000
=> 15x/8=62000
=> 15x=496000
=> x=496000/15
=> x=33067 .
Hence , mother contribute = 33067
Elder daughter contribute= 33067*3/8=12400
Younger daughter contribute= 33067/2=16533
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