A mother and her two daughters got a room constructed for Rs.62,000. The elder daughter
contributes 3/8 of her mother’s contribution while the younger daughter
contributes 1/2 of her elder’s sister share.
1. If the amount contributed by mother is Rs x, then what fraction of mother’s amount
is contributed by younger sister?
(a) Rs.5x/16 (b) Rs. 5x/16 (c) Rs. 3x/16 (d) 7x/16
2. How much money is contributed by the mother?
(a) Rs.38680 (b) Rs. 39780 (c) Rs. 49680 (d) 39680
3. Find the difference of the amount contributed by two sisters.
(a) Rs.7440 (b) Rs. 9440 (c) Rs. 14880 (d) None of these
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Answer:
Solution :
Let mother contribute = x
Elder daughter contribute = 3/8*x = 3x/8 younger daughter contribute = x/2
Total contribution = 62000
According to the given question -
=> x+3x/8+x/2=62000
=> (8x+3x+4x)/8=62000
=> 15x/8-62000
=> 15x=496000
=> x=496000/15
=> x=33067.
Hence, mother contribute = 33067
Elder daughter contribute= 33067*3/8=12400
Younger daughter contribute= 33067/2=16533
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