Math, asked by fantasticpoonam7746, 1 month ago

A mother and her two daughters got a room constructed for Rs. 6,200,000. The elder daughter contributes 3 /8 of her mother’s contribution while the younger daughter contributes 2 /4 of her mother’s share.

Please answer step by step!! I really need help :(

Answers

Answered by monikaverma29036
0

Answer:

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Answered by hritikvijay547
0

Answer:

Given :

A mother and her two daughters got a room constructed for Rs 62,000. The elder daughter contributes 3/8 of her mother's contribution while her younger daughter contributes 1/2 of her mother's share.

To Find :

How much do the three contribute individually ?

Step-by-step explanation:

Solution :

Let mother contribute = X

Elder daughter contribute = 3/8*x = 3x/8

younger daughter contribute = x/2

Total contribution = 62000

According to the given question -

=> x+3x/8+x/2=62000

=> (8x+3x+4x)/8=62000

=> 15x/8=62000

=> 15x=496000

=> x=496000/15

=> x=33067.

Hence, mother contribute = 33067

mother contribute = 33067Elder daughter contribute= 33067*3/8=12400

mother contribute = 33067Elder daughter contribute= 33067*3/8=12400Younger daughter contribute= 33067/2=16533

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