A mother and her two daughters got a room constructed for Rs. 62,000. The elder daughter contributes 3/8 of her mother’s contribution while the younger daughter contributes 1/2 of her mother’s share. How much do the three contribute individually?
Answers
Step-by-step explanation:
Let the moher's share be Rs. x
Now, elder daughter's share
=
R
s
.
3
8
x
and younger daughter's share
=
R
s
.
1
2
x
According to the question,
x
+
3
8
x
+
x
2
=
62000
⇒
8
x
+
3
x
+
4
x
8
=
62000
⇒
15
x
=
62000
×
8
⇒
x
=
62000
×
8
15
⇒
x
=
12400
×
8
3
⇒
x
=
99200
3
=
33066.6
So, mother's share = Rs. 33066.6
Elder daughter's share
=
3
8
×
99200
3
=
R
s
.
12400
Younger daughter's share
=
1
2
×
99200
3
=
R
s
.
16533.3
Hence, mother and her two daughters contributed Rs. 33066.6, Rs. 12400 and Rs. 16533.3 respectively.
Answer:
Mother contributed Rs. ≈ rupees
Elder daughter contributed Rs.
Younger daughter contributed Rs. .
Step-by-step explanation:
The total expenditure for room construction rupees.
A mother and her two daughters together paid the amount.
We need to find each one's share, certain clues are given.
Elder daughter and younger daughter contributed and of mother's contribution respectively.
So let us take the contribution of mother
Therefore the contribution of elder daughter
and the contribution of younger daughter
And the total sum would be . . . . (1)
From this equation we can find the value of .
(1) ⇒ (making denominators equal)
So the mother contributed Rs.
Hence the elder daughter contributed rupees,
and younger daughter contributed rupees
Hence the answer
thank you