A mother and her two daughters got a room constructed for
Rs. 62,000. The elder daughter contributes
3/
8 of her mother’s
contribution while the younger daughter contributes
1
/2 of her
mother’s share. How much do the three contribute individually?
Answers
Answered by
14
Let us assume, the mother contribution in the construction is Rs x.
Therefore, elder daughter's contribution is Rs 3x/8 and younger daughter contribution is Rs x/2
Hence,
x + 3x/8 + x/2 = 62000
Multiply the equation by 8 on both sides
8x + 3x + 4x = 62000 * 8
15x = 496000
x = 33066.67
Mother's contribution is Rs 33066.67
Elder daughter's contribution is 3/8 * 33066.67 = Rs 12400
Younger daughter's contribution is 1/2 * 33066.67 = Rs 16533. 335
Therefore, elder daughter's contribution is Rs 3x/8 and younger daughter contribution is Rs x/2
Hence,
x + 3x/8 + x/2 = 62000
Multiply the equation by 8 on both sides
8x + 3x + 4x = 62000 * 8
15x = 496000
x = 33066.67
Mother's contribution is Rs 33066.67
Elder daughter's contribution is 3/8 * 33066.67 = Rs 12400
Younger daughter's contribution is 1/2 * 33066.67 = Rs 16533. 335
Answered by
3
let mother contributed x rs
1 daughter 3/8x
2 daughter1/2x
x+3/8x+1/2x=62000
15/8x=62000
x=62000*8/15
x=33066.666
1 daughter=12400
2 daughter=16533.33
1 daughter 3/8x
2 daughter1/2x
x+3/8x+1/2x=62000
15/8x=62000
x=62000*8/15
x=33066.666
1 daughter=12400
2 daughter=16533.33
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