Math, asked by prakhar3010, 1 year ago

A mother and her two daughters got a room constructed for

Rs. 62,000. The elder daughter contributes

3/
8 of her mother’s

contribution while the younger daughter contributes

1
/2 of her

mother’s share. How much do the three contribute individually?

Answers

Answered by tejasmba
14
Let us assume, the mother contribution in the construction is Rs x.

Therefore, elder daughter's contribution is Rs 3x/8 and younger daughter contribution is Rs x/2

Hence,

x + 3x/8 + x/2 = 62000

Multiply the equation by 8 on both sides

8x + 3x + 4x = 62000 * 8

15x = 496000

x = 33066.67

Mother's contribution is Rs 33066.67
Elder daughter's contribution is 3/8 * 33066.67 = Rs 12400
Younger daughter's contribution is 1/2 * 33066.67 = Rs 16533. 335
Answered by student10
3
let mother contributed x rs
1 daughter 3/8x
2 daughter1/2x
x+3/8x+1/2x=62000
15/8x=62000
x=62000*8/15
x=33066.666
1 daughter=12400
2 daughter=16533.33
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