Question

A mother and her two sons got a room constructed for $60000 the elder son contributes 3/8 of his mother contribution while the younger son contributes 1/2of his mother,s share how much do the three contribute individually

Answer 1

Answer:

mother's contribution=32000

elder son's = 3x/8= 12000

younger son's = 1x/2= 16000

Step-by-step explanation:

let mother's share be x

then,

        x+3x/8+1x/2=60000

taking lcm,

                   (8x+3x+4x)/8=60000

                    15x=480000

                     x=480000/15

                     x=32000

Answer 2

Answer:

Step-by-step explanation:

let the mother's share be x;

so elder son's share =  x*3/8;

younger son's share be =x*1/2;

So, total is = 1

=> i.e., x + x*3/8 + x*1/2 =1;

=> x = 8/15;

so mothers share = 8/15;

hence mother's share = 8/15 *60000 = ₹32000;

elder son's share =  8/15 * 3/8 = 1/5;

hence elder son's share = 1/5 * 60000 = ₹12000;

younger son's share be =8/15 *1/2  = 4/15;

hence younger son's share = 4/15 *6000 = ₹16000;