A mother and her two sons got a room constructed for Rs.60,000. The Elder son contributes 3/8 of his mother's contribution while the younger son contributes 1/2 of his mother's share .How much do the three contribute individually?
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Answered by
3
Let the share of mother be x
Hence, share of elder son = 3/8 of x
share of younger son = 1/2 of x
Given, total share = 60000
share of mother + share of elder son + share of younger son = 60000
=> x + ( 3 / 8 of x ) + ( 1 / 2 of x ) = 60000
=> x + ( 3x / 8 ) + ( x / 2 ) = 60000
=> ( 8x + 3x + 4x ) = 480000
=> 15x = 480000
=> x = 32000
Hence,
Share of mother = x = Rs 32000
share of elder son = 3x / 8 = 3(32000)/8 = Rs12000
Share of younger son = 32000/2 = 16000
Answered by
4
let the contribution of mother be x
so according to condition given
3/8(x)+1/2 (x)+x=60,000
solving this
30/16 (x)= 60,000
from this we get x = 32,000
contribution of elder sun = 32000×3/8=12000
contribution of younger son= 32000×1/2=16000
so according to condition given
3/8(x)+1/2 (x)+x=60,000
solving this
30/16 (x)= 60,000
from this we get x = 32,000
contribution of elder sun = 32000×3/8=12000
contribution of younger son= 32000×1/2=16000
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