Question

A mother divides 36 sweets between her children "A" and "B" such that half of the share of "A" is three less than the share of "B".
O 12
B.
09
C.
O 14
07​

Answer 1

Given :- A mother divides 36 sweets between her children "A" and "B" such that half of the share of "A" is three less than the share of "B".

To Find :- Share of B ?

A) 12

B) 9

C) 14

D) 7 .

Solution :-

Let us assume that, share of A is a and share of B is b.

Now, we have given that,

→ Half of share of A = 3 less than share of B .

So,

→ (a/2) = b - 3

→ a = 2(b - 3)

→ a = 2b - 6

→ 2b - a = 6 --------- Eqn.(1)

Also, total sweets are 36.

So,

→ a + b = 36 --------- Eqn.(2)

Adding Eqn.(1) and Eqn.(2) we get,

→ 2b - a + a + b = 36 + 6

→ 3b = 42

dividing both sides by 3,

→ b = 14. (Ans.) (Option C) .

Hence, share of B is 14 sweets.

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Answer 2

Let A=x,B=36-x.
x/2 = 36-x-3
x=22
A=22
B=14