Math, asked by helpingsakshi, 2 months ago

a mother , her 2 daughter and a son got a house constructed for rupees 2500000 the elder daughter contributed 1/4th of her mother's contribution , the younger daughter's contribution was 1/5th of her mother's contribution and the son contributed 1/2 of his mother's contribution . how much did the four contribute individually​

Answers

Answered by Anupamraj1234
3

Answer:

a mother , her 2 daughter and a son got a house constructed for rupees 2500000 the elder daughter contributed 1/4th of her mother's contribution , the younger daughter's contribution was 1/5th of her mother's contribution and the son contributed 1/2 of his mother's contribution . how much did the four contribute individually

Answered by HariesRam
5

Step-by-step explanation:

From the question it is given that,

A mother and her two daughters got a room constructed for = ₹ 62,000

Let us assume mother’s share be x,

Then,

The elder daughter’s contribute = 3/8 of her mother’s share

= 3/8 x

The younger daughter’s contribute

= ½ of her mother’s share = ½ x

So,

mother’s share + elder daughter’s share + younger daughter’s share

= ₹ 62,000 x + (3/8) x + ½ x = ₹ 62,000

The LCM of the denominators 1, 8 and 2 is 8

(1/1) = [(1×8)/ (1×8)] = (8/8)

(3/8) = [(3×1)/ (8×1)] = (3/8)

(1/2) = [(1×4)/ (2×4)] = (4/8)

Then,

(8/8) x + (3/8) x + (4/8) x = 62,000

(8x + 3x + 4x)/8 = 62,000

(15x/8) = 62,000

15x = 62,000 × 8

X = 496000/15

X = ₹ 33,066.6

Mother’s share = ₹ 33,066.6

Elder daughter’s share = 3/8 of her mother’s share

= 3/8 x

= 3/8 × 33066.6

= ₹ 12,400

Younger daughter’s share

= ½ of her mother’s share

= ½ x = ½ × 33066.6

= ₹ 16,533.3

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