A mother her little daughter and her just born infant boy together stood on a weighing machine which shows 74kgs.how much does the daughter weigh if the mother weighs 46kg more than the combined weight of daughter and the infant and the infant weighs 60% less than the daughter.
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let a, b and c be the ages of mother daughter and infant respectively
a+b+c=74
a=b+c+46 (given)
c=b-60%of b
c=0.4b
in eq 1
b+c+46+b+c=74
b+0.4b+b+0.4b=28
2.8b=28
b=10kgs(weight of daughter)
c=4kgs(of infant)
and a =60kgs(of mom)
a+b+c=74
a=b+c+46 (given)
c=b-60%of b
c=0.4b
in eq 1
b+c+46+b+c=74
b+0.4b+b+0.4b=28
2.8b=28
b=10kgs(weight of daughter)
c=4kgs(of infant)
and a =60kgs(of mom)
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