Question

a mother is 24 year old than her son after 4 year the age of mother will be twice of the age of mother will be twice of the age of her son find the present age mother and son
​

Answer 1

Appropriate Question :

A mother is 24 year older than her son after 4 year the age of mother will be twice of the age of her son. Find the present age mother and son.

Given :

• Mother is 24 years old than her son.

• After 4 years, the age of mother will be twice the age of her son.

To find :

• Present age of mother

• Present age of son

Solution :

Let us assume the present age of the son as x years and the age of mother as x + 24 years.

Their ages after 4 years :-

→ Mother's age = x + 24 + 4

→ Mother's age = x + 28 years

→ Son's age = x + 4 years

According to the question :-

→ Age of mother = 2(Age of son)

→ x + 28 = 2(x + 4)

→ x + 28 = 2x + 8

→ 28 - 8 = 2x - x

→ 20 = x

→ The value of x = 20

Substitute the value of x in the ages of mother and her son :-

→ Mother's age = x + 24

→ Mother's age = 20 + 24 = 44 years

→ Son's age = x = 20 years

Therefore, the present age of mother and her son is 44 years and 20 years respectively.

Answer 2

Answer:

Let the age of son is X

Mother's age = X + 24

After 4 year mother's age = X + 24 + 4 = X + 28

Son's age = 2X

2X = X + 28

2X - X = 28

X = 28

Present age of son is 28 years

Present age of mother is 28 + 24 = 52 years