Question

A mother is 3 times as old as her son. After 15 years, her age will be twice the age
of her son. Find their present ages.
​

Answer 1

In 15 years, she'll be M+15 and he'll be S+15

M%2B15=2%28S%2B15%29

M%2B15=2S%2B30

M=2S%2B15

Substitute from the first equation.

3S=2S%2B15

highlight%28S=15%29years old

Then from the first equation,

M=3%2815%29

highlight%28M=45%29 years old

Answer 2

Answer:

Let the son's age now be x years.  

Then, Mother's age now =3x years.

After 15 years, son's age =(x+15) years

Mother's age =(3x+15) years

Given, (3x+15)=2(x+15)

⇒3x+15=2x+30

⇒3x−2x=30−15

⇒x=15

∴ Son's age now =15 yrs. and Mother's age now =3×15=45 yrs.

I HOPE IT HELP YOU!

Step-by-step explanation: