Question

A mother is 7 times as old as daughter. Two years ago , the mother was 13 times as old as her daughter . find their present age

Answer 1

Let the daughter's age be x.

Then mother's age = 7x

TWO YEARS AGO:

Daughter's age = x - 2

Mother's age = 7x - 2

ACCORDING TO QUESTION:

7x - 2 = 13 (x - 2)

7x - 2 = 13x - 26

6x = 24

x = 4 years

HENCE THE PRESENT AGE OF DAUGHTER IS 4 YEARS AND MOTHER'S AGE = 7*4 = 28 YEARS

Answer 2

Answer:

4 years

Step-by-step explanation:

let daughter age be x

two Years ago

daughter age be x-2

mother age be 7x-2

according to questions

7x-2=13(x-2)

7x-2=13x-26

=-2+26=13x-7x

=6x =24

=24/6

=x =4 years