Question

A mother is 7 times as old as her daughter
two years ago she was 13 times as old as her daughter find he present age​

Answer 1

Answer:

Mother's age = 28 years

Daughter's age= 4 years

Step-by-step explanation:

Let the daughter's age be x.

Then mother's age = 7x

TWO YEARS AGO:

Daughter's age = x - 2

Mother's age = 7x - 2

ACCORDING TO QUESTION:

7x - 2 = 13 (x - 2)

7x - 2 = 13x - 26

6x = 24

x = 4 years

HENCE THE PRESENT AGE OF DAUGHTER IS 4 YEARS AND MOTHER'S AGE = 7*4 = 28 YEARS

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