A mother is 9 times as old as her son. in five years, she will be 5 times her son's age then. find her present age.
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let present age of son be x
present age of mother =9x
in five years,
age of son=x+5
age of mother =9x+5
ATC,
9x+5=5(x+5)
9x+5=5x+25
4x=20
x=5
age of mother=9*5
=45 years
present age of mother =9x
in five years,
age of son=x+5
age of mother =9x+5
ATC,
9x+5=5(x+5)
9x+5=5x+25
4x=20
x=5
age of mother=9*5
=45 years
tharun54:
hi
Answered by
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let the present age of child is x
present age of mother be y
ATQ
y=9x
after 5 years
y+5 =5(x+5)
y+5=5x+25
9x+5=5x+25
4x=20
x=5
present age of mother 9x
b. b. 45
present age of mother be y
ATQ
y=9x
after 5 years
y+5 =5(x+5)
y+5=5x+25
9x+5=5x+25
4x=20
x=5
present age of mother 9x
b. b. 45
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