Question

a mother is four times as old as her daughter.if the difference of their ages is 36 years.find the age of the daughter​

Answer 1

Answer:

let the daughter age be X

then 4 times become 4x

4x = 36

X = 36/4

X = 9

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Answer 2

Answer:

let the age of the daughter be X and her mother be 4X

A/ Q

= 4X- X= 36

= 3X=36

= X=12

therefore, the daughter's age is X=12 Yrs

the age of the mother is 4X=4x 12

=48yrs