Question

A mother is three times as old as her son.after 12 years her age will be twice as the age of her son.Find their present ages. ​

Answer 1

Answer:

Son's age =12

Mother's age =36

Step-by-step explanation:

Let son's age be x

Mother's age = 3x

After 12 years:-

Mother's age = 3x+12

Son's age = x+12

According to question

3x+12 = 2(x+12)

3x+12 = 2x+24

3x-2x = 24-12

x = 12

Mother's age = 3×12 = 36

Son's age = 12yrs

Mother's age = 36yrs

Answer 2

Answer:

MOTHER'S PRESENT AGE =36

SON'S PRESENT AGE =12

Step-by-step explanation:

LET SON'S AGE = X

SO' MOTHER'S AGE WILL BE 3X

AFTER 12 YEARS -

• MOTHER'S AGE WILL BE 3X + 12

• SON'S AGE WILL BE X+ 12

ATQ,

3X + 12 = 2[X+12]

3X + 12 = 2X + 24

3X - 2X = 24 - 12

X = 12

SO

• SON'S AGE IS 12
• MOTHER'S AGE IS 3 * 12 = 36