Question

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother? A 43 years

Answer 1

Step-by-step explanation:

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother A 43 years......

Answer 2

Given:

The mother's age is twice the son's age.

To find:

The present age of the mother.

Solution:

Let the mother's present age = X years

Let the son's current age = Y years

Since the age of the mother is twice the age of the son,

Therefore,

X = 2Y                                ( equation 1)

Twenty years ago, the age of the mother would be (X-20) years,

The age of the son would be (Y-20) years

Twenty years ago,

The mother's age was ten times the age of the son.

Therefore,

X- 20 = 10 × (Y-20 )         ( equation 2)

Putting X = 2Y in equation 2,

2Y – 20 = 10Y - 200

200 – 20 = 10Y – 2Y

180 = 8Y

Y = 22.5 years

Now, X= 2Y

X = 2 × 22.5

X = 45 years

The mother's present age is 45 years.