Question

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

38 years

40 years

43 years

45 years

​

Answer 1

Answer:

45 years

Step-by-step explanation:

let the present age of the mother be 'x' and that of her son be 'y'

given that x = 2y

20 years ago,

(x-20) = 10 (y-20)

x - 20 = 10y - 200

x - 5x  = -200 + 20   [(x = 2y) ∵ 10y = 5x]

-4x = -180

x = 180/4 = 45