Question

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?​

Answer 1

Let the present age of the Son be - x

then,

present age of Mother will be - 2x

Now, 20 years ago, their ages wil be 20 years less., i.e

Mother - (2x-20) & Son - (x - 20)

Then, according to given condition, Mother was 10 times the age of son, so the equation becomes :-

(2x - 20) = 10(x - 20)

(2x - 20) = (10x - 200)

8x = 180

x = 180/8

x = 22.5 (This is the age if Son)

And Mother is twice as old as her son,

So, Mothers age will be - 2X

i.e., 2 * 22.5 = 45

Hence, Mother is 45 years old !!

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