Question

A mother is twice as old as her son. If 20 years ago, the age of the mother was 10 times the age of the son, what is the present age of the mother?

A) 38 years
B )40 years
C) 43 years
D} 45 years

I will mark your answer as brainliest only if u will explain me tooo

Answer 1

Answer:

The Correct answer is (D)

Step-by-step explanation:

Let the age of son = X years

∴Age of mother would be =2X

As per question 20 years ago;

10 (X -20) = 2X - 20

10X - 200 = 2X - 20

10X - 2X= - 20 + 200

8X = 180

X = Problem on ages 13= 22.5 years

∴Age of mother = 22.5 * 2 = 45 years

Hope it helps:)