Question

A mother's age is 2 years more than four times to that of the son's age.If the mother's age is 30 years,find the age of the son.​

Answer 1

Answer:

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A mother's age is 2 years more than four times to that of the son's age.If the mother's age is 30 years,find the age of the son.

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Let the son’s age be n and the Mum’s age be 4n.

In 16 years the son will be n + 16 and the mother will be 4n + 16. Under which circumstances will she be twice her son’s age?

So when will 4n + 16 (mother’s new age) be equal to 2(n + 16) (twice the son’s new age)?

Compare:

4n + 16 = 2n + 32

2n = 16

∴ n = 8

So initially, the son is 8 and the mother is 32, four times the son’s age.

In 16 years’ time the son will be 24 and the mother will be 48, double his age.

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Answer 2

$\large\color{lime}\boxed{\colorbox{black}{Answer : - }}$

$Let \: the \: age \: of \: the \: son \: be \: 'x'$

$Then \: the \: age \: of \: the \: mother \: will \: \\ be \: 2 \: + \: 4x.$

$∴ \: 4x + 2 = 30$

$= > 4x = 30 - 2$

$= - 28$

$= > x = \frac{28}{4}$

$= 7 \: years$

$\color{red}∴ \: The \:son \: \: age \: i s \: 7 \: years.$