Question

A mother say her daughter "5 year ago I was 5 themes old as you but 10 years hence I shall be only twice as old as you be. find the present age of mother and daughter​

Answer 1

Answer:

let the age of mother be X

and the age of daughter be Y

on 1st condition

X-5 = 5 ( Y - 5)

X-5 = 5Y-25

5Y - X -20 = 0...(1)

ON 2ND CONDITION

X + 10 = 2 ( Y + 10)

X + 10 = 2Y +20

2Y - X + 10 = 0..(2)

Step-by-step explanation:

THE PRESENT AGE OF MOTHER AND DAUGHTER SHOULD BE THE COMMON SOLUTION

Answer 2

Answer:

Present age of Mother is 30 years and Daughter is 10 years.

Step-by-step explanation:

Solution :

5 years ago,

Let,

Age of Daughter = x

Age of Mother = 5x

Present age of Daughter = x + 5

Present age of Mother = 5x + 5

After 10 years,

Age of Daughter = x + 5 + 10 = (x + 15)

Age of Mother = 5x + 5 + 10 = ( 5x + 15)

Also,

Age of Mother twice as old as her Daughter's age

So,

⇒ 2 (x + 15) = 5x + 15

⇒ 2x + 30 = 5x + 15

⇒ 2x - 5x = 15 - 30

⇒ - 3x = - 15

⇒ 3x = 15

⇒ x = 15 / 3

⇒ x = 5

Present age of Daughter = x + 5

⇒ 5 + 5

⇒ 10

Present age of Daughter = 10 years

Present age of Mother = 5x + 5

⇒ 5 (5) + 5

⇒ 25 + 5

⇒ 30

Present age of Mother = 30 years

Therefore, present age of Mother is 30 years and Daughter is 10 years.