A mother spider climbs up a wall 4 cm at a time while a baby spider climbs up only 3 cm at a time. If they start from same point at what distance will they meet again
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12cm
as the mother has to climb 4cm at a time,
and the baby spider climbs 3cm at a time, 12 is a common multiple between them, so,
mother = 4×3= 12
and baby spider= 3×4= 12
therefore they will meet each other at 12cm distance
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Answer:
12 cm surely they will meet!
Step-by-step explanation:
lcm of 4 and 3= 12cm
or
practically see my picture
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