Question

a mother was 7 times as old as her daughter 5 years ago. she were be 3 times as old as her daughter after 5 years. find the present ages of both.
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Answer 1

Answer:

Let the mothers age be M and the daughters D

M - 5 = 7(D-5)

M = 7D - 30

M + 5 = 3(D + 5)

M = 3D + 10

so

7D - 30 = 3D + 10

4D = 40

D = 10 (Daughter is currently 10 years old)

M = 3D + 10

M = 40 (Mother is currently 40)