A motocylist drives from place A to B with a uniform speed of 30 in h`-1 and retur from place B to A with uniform speed of 20 km h-1 find its average speed
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Answered by
1
hey mate
here is the answer..
Answer:
the average speed:
2xy/x+y
=>2*30*20/(30+20)
=>1200/50
=>24 km/hr
explanation:
let the distance between a and b between be D km .
let the speed be x km/hr to travel from a to b.
let the speed be y km/hr to travel from b to a.
thus,
time to travel from a to b=D/x hr
time to travel from b to a =D/y
thus,
the average speed=total distance/total time
=(D+D)/(D/x+D/y)
=2D/D(x+y)/xy
=2xy/x+y
aditisrivastava23:
please bhaiya give me solution which I will write in my fair copy
This will also wright but still I am confuse
plz brother give me solution
hey sis, I have edited my answer so that you can write it in your fair copy!
Tnx bhaiya a lot of thankyou
Answered by
1
short cut for this example is
if travelld distance in first and last moment 8s same then,
avg. speed= 2xy/x+y
where as x and y are two speed with which we travel
there fore ans.= 24kmph
if travelld distance in first and last moment 8s same then,
avg. speed= 2xy/x+y
where as x and y are two speed with which we travel
there fore ans.= 24kmph
how
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