Question

A motor bik initally moving at 18km/h, accelerates at a rate of 5m/s square for 5 seconds. Calculate the distance covered by it from the start and the final velocity

Answer 1

Given :

• Initial velocity, u = 18 km/h = 5 m/s
• Time taken, t = 5 seconds
• Acceleration, a = 5 m/s²

To Find :

• Final velocity, v &
• Distance covered by the motor bike

According to the question,

We know,

➝ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time taken

➝ v = 5 + 5 × 5

➝ v = 5 + 25

➝ v = 30 m/s

Now, we will find the distance covered by the motor bike.

➝ s = ut + ½ at²

Where,

• s = Distance
• u = Initial velocity
• t = Time taken
• a = Acceleration

➝ s = 5 × 5 + ½ × 5 × 5 × 5

➝ s = 25 + ½ × 125

➝ s = 25 + 62.5

➝ s = 87.5 m

• Hence, the final velocity is 30 m/s and the distance covered by the motor bike is 87.5 m.

Answer 2

Given :-

A motor bike initally moving at 18km/h, accelerates at a rate of 5m/s square for 5 seconds

To Find :-

The distance covered by it from the start and the final velocity

Solution :-

We know that

1 km/h = 5/18 m/s

18 kmh = 18 × 5/18 = 5 m/s

s = ut + 1/2 at²

s = (5)(5) + 1/2 × (5) × (5)²

s = 25 + 1/2 × 5 × 25

s = 25 + 1/2 × 125

s = 25 + 125/2

s = 25 + 62.5

s = 87.5 m

Now

a = v - u/t

5 = v - 5/5

5 × 5 = v - 5

25 = v - 5

25 + 5 = v

30 = v

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