Question

a motor bike initially at rest picks up a velocity of 72 km per hr over a distance of 40m.calculate the acceleration

Answer 1

Dear Friend,
u=0kmph=0m/s
v=72kmph=20m/s
S=40m
2as=v^2-u^2
2a×40=20×20-0×0
80a=400
a=5m/s^2
Hope it helps u.

Answer 2

Hey Friend !

Initial Velocity = u = 0

Final Velocity = v = 72km/hr
= 72 x 5/18
= 20 m/s

Distance = s = 40 metres

Acceleration = a

Equation of motion :-

v² - u² = 2as

20² = 2×a×40

400 = 80a

a = 400/80

a = 5 m/s²



Hope this Helps You !

@Deepika
Brainly Moderator