Question

A motor bike initialy moving at 18 km/hr acclerates at a rate of 5m/s² for 5 second. calculate total distance covered​

Answer 1

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Given data:-

➤ Initial velocity of the bike (u) = 18 km/hr = 5 m/s

➤ Final velocity = Let "v"

➤ Acceleration (a) = 5 m/s²

➤ Time (t) = 5 sec

➤ Distance = Let "s"

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Solution:-

We use the equation,

$\bold{s = ut + \frac{1}{2} a {t}^{2} }$

By substituting the values in the given equation, after the calculation,

we get,

s = 87.5 m

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To find the final velocity, we use the equation,

v = u + at

Substituting values in the above equation,

we get,

$\bold {final \: velocity = \boxed{30 \: m/s}}$

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Hence, shown.