Question

A motor bike running at 90 km per hour in 2.5 sec calculate accelaration and distance covered in time

Answer 1

S=90kmph
S=90*5/18=20mps

T=2.5s

$d = s \times t$
D= 20*2.5=50m
$a = d \div {s}^{2}$
A=50/(2.5*2.5)=8m/s^2