A motor bike running at 90 kmh-1 is slowed down at 18kmh-1 in 2.5m. calculate:
a. Acceleration.
b. Distance covered in time it’s slow down
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t=2.5min
t=2.5/60 seconds
t=0.04s
a)
a=90-18/0.04
a=1800 km/s^
b)d=speed ×time
d=72×0.04
d=2.88km.
hope it helps you.
if you want to change speed in m/s so change it and solve it as usual.
mark as brainliest
t=2.5/60 seconds
t=0.04s
a)
a=90-18/0.04
a=1800 km/s^
b)d=speed ×time
d=72×0.04
d=2.88km.
hope it helps you.
if you want to change speed in m/s so change it and solve it as usual.
mark as brainliest
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