a motor bike running at speed of 5 m/s , picks up a velocity of 35 m/s in 6 sec . calculate it's acceleration
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Answered by
7
hey dear
here is your answer
INITIAL velocity = 5 m/s
final velocity = 35m/s
time = 6 seconds
acceleration = ?
by the first equation of motion
v = u+at
35 = 5+6a
6a = 30
a = 5m/s²
hope it helps :)
here is your answer
INITIAL velocity = 5 m/s
final velocity = 35m/s
time = 6 seconds
acceleration = ?
by the first equation of motion
v = u+at
35 = 5+6a
6a = 30
a = 5m/s²
hope it helps :)
Answered by
3
HER THE GIVEN DATA
SPEED = 5M/S
VELOCITY(V) = 35M/S
TIME = 6 SECONDS
WE KNOW THAT
SPEED = DISTANCE / TIME
AS PER QUESTION
5 = DISTANCE /6
DISTANCE COVERED = 5 * 6
= 30M
WE KNOW THAT
S = UT + 1/2 AT*2
30 = 35 + 1/2 *A * 36
A =1.66M/S*2
THEREFORE THE ACCELERATION = 1.6M/S*2
SPEED = 5M/S
VELOCITY(V) = 35M/S
TIME = 6 SECONDS
WE KNOW THAT
SPEED = DISTANCE / TIME
AS PER QUESTION
5 = DISTANCE /6
DISTANCE COVERED = 5 * 6
= 30M
WE KNOW THAT
S = UT + 1/2 AT*2
30 = 35 + 1/2 *A * 36
A =1.66M/S*2
THEREFORE THE ACCELERATION = 1.6M/S*2
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