Question

A motor boat in lake starting from rest,accelerates a straight path at a uniform rate of 2.0 ms-2 for 10.0s. How far does the boat travel during this time ?

Answer 1

Given:

Acceleration = 2 m/s²

Time = 10 sec

Initial velocity = 0 m/s

To find:

Distance travelled by the boat in that time interval

Concept:

Since the acceleration is constant we can easily apply the equation of kinematics to determine the distance travelled by the body in the time interval.

Calculation:

$s = ut + \frac{1}{2} a {t}^{2}$

$= > s = (0 \times 10) + \{ \frac{1}{2} \times 2 \times {(10)}^{2} \}$

$= > s = 100 \: m$

So final answer is :

Distance travelled is 100 m

Answer 2

Answer:

100 m

Explanation:

Given :

Initial velocity u = 0 m / sec  [ Starting from rest ]

Acceleration a = 2 m / sec²

Time t = 10 sec

We're asked to find distance s ! :

Using second equation of motion :

s = u t + 1  / 2 a t²

Substituting values in equation we get :

s = 0 × 10 + 1 / 2 × 2 × 10² m

= > s = 0 + 10² m

= > s = 100 m

Therefore , boat travel 100 m distance!