Question

A motor boat is moving in a straight line . it's velocity is V when the motor boat is shut off. If the retardation at any subsequent time equal to the magnitude of its velocity at that time find its velocity and distance traversed in time t after the motor is shut off​

Answer 1

$\huge\red{Answer}$

➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️

It is a differential equation,if we want to find velocity at time t . First arrange the given equation like as

dv/dt=-kv^2

dv/v^2=-kdt

On integrating

-1/v=-kt

v=1/kt

If Vo is the velocity at the time of cut off then velocity after time t

As the Ist equation of motion is applying

V=Vo-at

Where a=-kv^2

But at time t

a=-k/k^2t^2=-1/kt^2

V=Vo+(1/kt^2)

jai siya ram☺ __/\__

➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️

¯\_(ツ)_/¯

Answer 2

Answer:

Refers to the attachment....